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8x^2+63x+8=0
a = 8; b = 63; c = +8;
Δ = b2-4ac
Δ = 632-4·8·8
Δ = 3713
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-\sqrt{3713}}{2*8}=\frac{-63-\sqrt{3713}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+\sqrt{3713}}{2*8}=\frac{-63+\sqrt{3713}}{16} $
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